Energy Saving Calculation During Mild Weather

(when the outdoor is colder than the kitchen)

Below calculations are
based on reverse Carnot cycle (not the vapor compression cycle).
The vapor compression cycle is the one used in the actual
refrigerators. The reverse Carnot cycle is a hypothetical cycle
that real devices don't use. For more accurate vapor compression
cycle please see the notes of Mr. Pei-feng Hsu, Ph.D. Professor & Department Head Mechanical & Aerospace Engineering Department of Florida Inst. of Technology.

The following energy saving calculation and the resulting formula: **H = ****(****C - B) / ****(C - D)** have also been reviewed and verified by a third party expert. The resulting formula is used in a Spreadsheet
to show the energy saving rate based on different indoor and outdoor
temperatures.

For
an accurate comparison, it is assumed that both refrigerators/freezers (**R/Fs**)
have the exact same power, motor, compressor, cubic volume, and component
efficiencies. All external
environmental variables are likewise assumed to be the same, such as the inside
temperature of the R/Fs, the room temperature, the type and amount of
refrigerant, the number of times the R/Fs' doors are opened and closed, etc. Therefore all functional inefficiencies occur equally on both sides of the equation and cancel each other out and have no impact on the results of the calculations.

Basic math skills is the only requirement to understand the following calculations.

Wi = Work or electricity consumption of the Indoor R/F.

Ww = Work or electricity consumption of the Window R/F.

Qi = Heat absorbed by the evaporator of the Indoor R/F.

Qw = Heat absorbed by the evaporator of the Window R/F.

Qw = Qi Since both R/Fs are identical - else comparison would be partial.

Ti = temperature difference between Indoor R/F's condenser and evaporator.

Tw = temperature difference between Window R/F's condenser and evaporator.

H = The Energy (electricity) Savings % = 1- (Ww / Wi)

COP = Q / W (or W = Q / COP). The higher the COP the better, because more heat can be transferred with less work (electricity). The COP depends primarily on the temperature of the evaporator and the condenser. The closer the two temperatures, the higher the COP.

**W**w /
**W**i = (Qw/COPw) / (Qi/COPi) Since Qi = Qw Therefore **W**w /
**W**i = COPi / COPw

**COP** = cold temperature (**T**c) or the temperature of the evaporator, divided by
the temperature difference between the evaporator and the condenser (**T**d).

**COP <= T**c**
/ T**d

The
real COP will be considerably less than
**T**c**
/ T**d depending on the model of the
compressor, the type of refrigerant and other variables (which for accurate
comparison, we have assumed are exactly the same for both R/Fs (Indoor and
Window)). To simplify let's assume (for both R/Fs) the Real **COP** = 0.5 x **T**c / **T**d

Now going back to our
original table column definitions:** **

**B** = Outdoor
Temperature = the temperature of Window R/F's condenser.

**C** = Indoor Temperature
= the temperature of Indoor R/F's condenser.

**D** = The temperature of Indoor and Window R/F's evaporator.

**T**i = **C - D** = Temperature difference between the Indoor R/F's
evaporator and condenser.

**T**w = **B - D** = Temperature difference between the Window R/F's
evaporator and condenser.

Substituting these variables in our formula, we get:

**COPi = **0.5 x** D** / **T**i and **COP**w = 0.5 x** D** / **T**w

Or
alternatively:

**W**w / **W**i = **COP**i / **COP**w = (0.5 x** D** / **T**i) / ( 0.5 x**
D** / **T**w) = **T**w / **T**i

H =

All temperatures must be in Kelvin. However temperature differences (C-B) and (C-D) can be in Celsius because one Celsius is equal to one Kelvin.

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